\(\left(x-\dfrac{2}{3}\right)^3=\dfrac{1}{27}\)
=>\(\left(x-\dfrac{2}{3}\right)^3=\left(\dfrac{1}{3}\right)^3\)
=>\(x-\dfrac{2}{3}=\dfrac{1}{3}\)
=>\(x=\dfrac{1}{3}+\dfrac{2}{3}=\dfrac{3}{3}=1\)
`(x - 2/3)^3 = 1/27`
`=> (x - 2/3)^3 = (1/3)^3`
`=> x - 2/3 = 1/3`
`=> x = 1/3 + 2/3`
`=> x = 3/3`
`=> x = 1`
Vậy `x = 1`