Question

 x . $(6 - x )^{2019}$ = $(6 - x )^{2019}$

Answer 1

\(x\cdot\left(6-x\right)^{2019}=\left(6-x\right)^{2019}\\ \Leftrightarrow x\cdot\left(6-x\right)^{2019}-\left(6-x\right)^{2019}=0\\ \Leftrightarrow\left(x-1\right)\left(6-x\right)^{2019}=0\\ \Leftrightarrow\left[{}\begin{matrix}x-1=0\\\left(6-x\right)^{2019}=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=6\end{matrix}\right.\)

Vậy x ∊ {1; 6}

Answer 2

\(=>x\left(6-x\right)^{2019}-\left(6-x\right)^{2019}=0\)

\(=>\left(x-1\right)\left(6-x\right)^{2019}=0\)

\(=>\left[{}\begin{matrix}x-1=0\\6-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=6\end{matrix}\right.\)

Answer 3

Answer 4