\(\left(x-\dfrac{3}{4}\right)^2+1=\dfrac{25}{9}\)
\(\Rightarrow\left(x-\dfrac{3}{4}\right)^2=\dfrac{16}{9}\)
\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{4}{3}\\x-\dfrac{3}{4}=-\dfrac{4}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{25}{12}\\x=-\dfrac{7}{12}\end{matrix}\right.\)
#Toru
=>(x-3/4)^2=25/9-1=16/9
=>x-3/4=4/3 hoặc x-3/4=-4/3
=>x=25/12 hoặc x=-7/12