=>\(\sqrt{x}-\dfrac{3}{2}=\dfrac{1}{2}\) hoặc \(\sqrt{x}-\dfrac{3}{2}=-\dfrac{1}{2}\)
=>căn x=2 hoặc căn x=1
=>x=4 hoặc x=1
\(\left(\sqrt{x}-\dfrac{3}{2}\right)^2=\dfrac{1}{4}\\ \left(\sqrt{x}-\dfrac{3}{2}\right)^2=\left(\dfrac{1}{2}\right)^2\\ =>\left[{}\begin{matrix}\sqrt{x}-\dfrac{3}{2}=-\dfrac{1}{2}\\\sqrt{x}-\dfrac{3}{2}=\dfrac{1}{2}\end{matrix}\right.\\ \left[{}\begin{matrix}\sqrt{x}=-\dfrac{1}{2}+\dfrac{3}{2}\\\sqrt{x}=\dfrac{1}{2}+\dfrac{3}{2}\end{matrix}\right.\\ \left[{}\begin{matrix}\sqrt{x}=1\\\sqrt{x}=2\end{matrix}\right.\\ \left[{}\begin{matrix}x=1\\x=4\end{matrix}\right.\)
