Question

(x-2).(x+5) =0

Answer 1

\(\left(x-2\right)\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)

Answer 2

\(\left(x-2\right)\left(x+5\right)=0\)

⇔ \(\left[{}\begin{matrix}x-2=0\\x+5=0\end{matrix}\right.\)

⇔ \(\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)

Vậy ...

Answer 3

\(\left(x-2\right)\left(x+5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-2=0\\x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\)

Vậy \(x=\left\{2;-5\right\}\)

Answer 4

\((x-2).(x+5) =0 \)

\(\rightarrow \left[\begin{matrix} x-2=0\\ x+5=0\end{matrix}\right.\)

\(\rightarrow \left[\begin{matrix} x= 0 + 2\\ x=0-5\end{matrix}\right.\)

\(\rightarrow \left[\begin{matrix} x=2\\ x=-5\end{matrix}\right.\)

Vậy \(x \in \) { \(2 ; -5 \) } thì \((x-2).(x+5) =0 \)