Ta có : \(3x=1250+\dfrac{270}{\dfrac{3}{3}}=1250+\dfrac{270}{9}=1250+30=1280\)
\(\Rightarrow x=\dfrac{1280}{3}\)
Vậy ...
$-270 :3:3 + x .3 = 1250$
$\to -30 + 3x = 1250$
$\to 3x = 1280$
$\to x = \dfrac{1280}{3}$
Vậy : $ x = \dfrac{1280}{3}$
- 270 : 3 : 3 + X x 3 = 1250
- 270 : 9 + X x 3 = 1250
- 30 + X x 3 = 1250
X x 3 = 1280
X = \(\dfrac{1280}{3}\)
Ta có: \(x-270:3:3+x\cdot3=1250\)
\(\Leftrightarrow4x-30=1250\)
\(\Leftrightarrow4x=1280\)
hay x=320
Vậy: x=320
\(x-\dfrac{270}{3}:3+3x=1250\\ \Leftrightarrow x-30+3x=1250\\ \Leftrightarrow-2x=1280\\ \Rightarrow x=-640\)
\(x-270:3:3+x.3=1250\)
\(x.\left(1+3\right)-30=1250\)
\(x.4=1250+30\)
\(x.4=1280\)
\(x=1280:4\)
\(x=320\)