\(\dfrac{x-2}{3}=\dfrac{x+1}{4}\)
`=>4(x-2)=3(x+1)`
`=>4x-8 =3x+3`
`=>4x-3x=3+8`
`=> x= 11`
\(x-\dfrac{2}{3}=x+\dfrac{1}{4}\)
\(\Leftrightarrow x-x=\dfrac{2}{3}+\dfrac{1}{4}\)
\(\Leftrightarrow0=\dfrac{11}{12}\)
Vậy phương trình vô nghiệm
(x-2)/3 = (x+1)/4
=> 4(x-2)/3 = 3(x+1)/4
=> (4x-8)/12 = (3x+3)/12
=> 4x-8=3x+3
=> 4x-3x=8+3
=> x=11