Question

(x + 1)(x + 2) - (x - 3)(x + 4) = 6

Answer 1

\(\Leftrightarrow x^2+3x+2-\left(x^2+x-12\right)=6\\ \Leftrightarrow2x=-8\\ \Leftrightarrow x=-4\)

Answer 2

\(\left(x+1\right)\left(x+2\right)-\left(x-3\right)\left(x+4\right)=6\)

\(\Leftrightarrow x^2+3x+2-x^2-x+12=6\)

\(\Leftrightarrow2x=-8\)

hay x=-4

Answer 3

\(\left(x+1\right)\left(x+2\right)-\left(x-3\right)\left(x+4\right)=6\\ \Rightarrow x^2+3x+2-x^2-x+12=6\\ \Rightarrow2x=-8\\ \Rightarrow x=-4\)