\(\dfrac{x}{-13}=\dfrac{5}{6,5}\)
\(< =>6,5x=-65\)
\(=>x=-10\)
\(\dfrac{x}{-13}=\dfrac{5}{6,5}\\ =>x\cdot6,5=-13\cdot5\\ =>x\cdot6,5=-65\\ =>x=-65:6,5\\ =>x=-10\)
x+2015/5 + x+2016/4=x+2017/3 + x+2018/2
x+5/2015+x+4/2016+x+3/2017+x+2/2018
a) x+2015 phần 5 + x+2016 phần 4= x+2017 phần 3 + x+2018 phần 2
b) x+2015 phần 5 + x+2016 phần 6= x+2017 phần 7+ x+2018 phần 8
Những cái chữ phần là viết theo dạng phân số mình quên viết các bạn giúp mình với thank
Tim x
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
2/ tim x
\(\frac{x+2015}{5}+\frac{x+2016}{6}=\frac{x+2017}{7} +\frac{x+2018}{8}\)
3/ tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{99}{101}+\frac{1}{15}+... +\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)
\(\dfrac{x+1}{2019}+\dfrac{x+2}{2018}=\dfrac{x+3}{2017}+\dfrac{x+4}{2016}\)
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
Tìm x, biết:
a) | x - 2017 | = 2017 - x
b) | x - 2016 | + | x - 2017 | = 2018
c) | x - 1 | + | x + 3 | = 4
Tìm giá trị nhỏ nhất
P = 2018/x^2+2x+2017
Q = a^2018+2017/a^2018+2015
A = (x-3y)^2020+(y-2018)^2018
B = (x+y-5)^8+(x-2y)^4+2016
C = \x-2017\+\x-2018\
D = \x-2010\+\x-2011\+\x+2012\
Tìm x biết:
a) \(\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
b) \(\frac{x+4}{2016}+\frac{x+3}{2017}=\frac{x+2}{2018}+\frac{x+1}{2019}\)
