=>x-1=6 hoặc x-1=-6
=>x=-5 hoặc x=7
`(x-1)^2 =36`
`(x-1)^2 = (+-6)^2`
`=>[(x-1=6),(x-1=-6):}`
`=> [(x=6+1=7),(x=-6+1=-5):}`
Vậy `x in {7;-5}`
\(\left(x-1\right)^2=36< =>\left[{}\begin{matrix}x-1=-6< =>x=-5\\x-1=6< =>x=7\end{matrix}\right.\)
(x-1)2=36
(x-1)2= 62
=> \(\left[{}\begin{matrix}x-1=6\\x-1=-6\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}7\\-5\end{matrix}\right.\)
Vậy x \(\in\) {7;-5}