\(a=\dfrac{a+1}{a-2020}\)
\(=\dfrac{a-2020}{a-2020}+\dfrac{2021}{a-2020}\)
\(=1+\dfrac{2021}{a-2020}\) Vì a>2020
⇒\(1+\dfrac{2021}{a-2020}\text{≥}2\)
Min a=2 ⇔\(\dfrac{2021}{a-2020}=1\)
⇔\(a-2020=2021\)
⇔\(a=4041\)
\(a=\dfrac{a+1}{a-2020}\)
\(=\dfrac{a-2020}{a-2020}+\dfrac{2021}{a-2020}\)
\(=1+\dfrac{2021}{a-2020}\) Vì a>2020
⇒\(1+\dfrac{2021}{a-2020}\text{≥}2\)
Min a=2 ⇔\(\dfrac{2021}{a-2020}=1\)
⇔\(a-2020=2021\)
⇔\(a=4041\)
Cho ham so bac nhat y=mx+1
a, Tim mde ham so nghich bien ? Ve do thi ham so voi m=2
b, Tim m de do thi ham so qua M (3;2) . Ve do thi ham so voi m tim duoc
c , Chung to do thi ham so luon qua 1 diem co dinh voi moi gia tri cua m
.
tim GTNN cua A =2/(x-1) + 1/(3-x) voi 1< x<3
Cho bieu thuc P=\(\frac{a^2+\sqrt{a}}{a-\sqrt{a}+1}-\frac{2a+\sqrt{a}}{\sqrt{a}}+1\)
Rut gon bieu thuc P ( lam rui ) Biet a>1 Hay so sanh P voi tri tuyet doi cua P ( chua lam )Tim GTNN cua P ( chua lam )
Cho a>=2
Tim gtnn cua A=a+1/a
Cho \(a^2+b^2+c^2=a^3+b^3+c^3=1.\) Tính \(S=a^{2020}+b^{2020}+c^{2020}.\)
Cho a>=2
Tim gtnn cua A=a+1/a
tìm gtnn các biểu thức s a)x2+2x+2020
b)m2+4m-1
c)m2+m
d)x-2căn x+10
e)4x-8 căn x +2020
CMR: \(\left(4+a-3b\right)^{2020}.\left(3a-5b-1\right)^{2020}⋮16\) với mọi a,b nguyên