Question

Viết thành dạng tích luỹ thừa các tích sau:
1. 2.2.2.2
2. 3.3.3.3.3.3
3. (-2).(-2)
4. (-2(-2(-2)
5. (-3(-3(-3(-3
6. (1/2)(1/2)(1/2)
7. (-3/2)(-3/2)(-3/2)(-3/2)
8. (-2/3)(-2/3)(-2/3)
9.(7/-8)(7/-8)(7/-8)(7/-8)
10. x.x.x.x
11. (-x)(-x)(-x)(-x)(-x)
12. (2x)(2x)(2x)
13. (-3x)(-3x)(-3x)(-3x)
14. ( -4x/3) (-4x/3)
15: (1/x)(1/x)(1/x)(1/x)
16: (1/x)(1/x)(1/x)(1/x)(1/x)

Answer 1

^{_{Thương người như thể thương thân lần sau đăng ít thôi bạn >:}}

<sup><sub>`</sub></sup>2.2.2.2 = 2^4`

`3.3.3.3.3.3 = 3^6`

`(-2).(-2) = (-2)^2`

`(-2(-2)(-2)=(-2)^3`

`(-3(-3)(-3)(-3) = (-3)^4`

`(1/2)(1/2)(1/2) = (1/2)^3`

`(-3/2)(-3/2)(-3/2)(-3/2) = (-3/2)^4`

`(-2/3)(-2/3)(-2/3) = (-2/3)^3`

`(7/-8)(7/-8)(7/-8)(7/-8) = (7/(-8))^4`

`x.x.x.x=x^4`

`(-x)(-x)(-x)(-x)(-x) = (-x)^5`

`(2x)(2x)(2x) = (2x)^3`

`(-3x)(-3x)(-3x)(-3x) = (-3x)^4`

`( -4x/3) (-4x/3) = ((-4x)/3)^2`

`(1/x)(1/x)(1/x)(1/x) = (1/x)^4`

`(1/x)(1/x)(1/x)(1/x)(1/x) = (1/x)^5`

Answer 2

\(1,2^4\\2,3^6\\ 3,\left(-2\right)^2\\ 4,\left(-2\right)^3\\ 5,\left(-3\right)^4\\ 6,\left(\dfrac{1}{2}\right)^3\\ 7,\left(-\dfrac{3}{2}\right)^4\\ 8,\left(-\dfrac{2}{3}\right)^3\\ 9,\left(\dfrac{7}{-8}\right)^4\\ 10,x^4\\ 11,\left(-x\right)^5\\ 12,\left(2x\right)^3\\ 13,\left(-3x\right)^4\\ 14,\left(-\dfrac{4x}{3}\right)^2\\ 15,\left(\dfrac{1}{x}\right)^4\\ 16,\left(\dfrac{1}{x}\right)^5 \)

Answer 3

\(1, 2.2.2.2=2^4\)

\(2,3.3.3.3.3.3=3^6\)

\(3, (-2).(-2)=-2^2\)

\(4. (-2(-2(-2)=-2^3\)

\(5. (-3(-3(-3(-3=-3^4\)

\(6,=(\dfrac{1}{2})^3\)

\(7,\)\(=-\dfrac{3}{2}^4\)

\(8,=-\dfrac{2}{3}^3\)

\(9,\dfrac{7}{-8}^4\)

\(10,=x^4\)

\(11,=-x^5\)

\(12,=2x^3\)

\(14,\)\(=-\dfrac{4x}{3}^2\)

\(15,\dfrac{1}{x}^4\)

\(16,=\dfrac{1}{x}^5\)

 

Answer 4

1, 2.2.2.2=2\(^4\)

2,3.3.3.3.3.3=3\(^6\)

3, (-2).(-2)= (-2)\(^2\)

4,(-2).(-2).(-2)=(-2)\(^3\)

5,(-3).(-3).(-3).(-3)=(-3)\(^4\)

6,(1/2).(1/2).(1/2)=(1/2)\(^3\)

7, (-3/2).(-3/2).(-3/2).(-3/2)=( -3/2)\(^4\)

8,(−2/3).(−2/3).(−2/3)=(−2/3)\(^3\)

9,(7/−8).(7/−8).(7/−8).(7/−8)=(7/−8)\(^4\)

10, x.x.x.x=x\(^4\)

11,(−x).(−x).(−x).(−x).(−x)=(−x)\(^5\)

12,(2x).(2x).(2x)=(2x)\(^3\)

13,(−3x).(−3x).(−3x).(−3x)=(−3x)\(^4\)

14,(−4x/3).(−4x/3)=(−4x/3)\(^2\)

15,(1/x).(1/x).(1/x).(1/x)=(1/x)\(^4\)

16,(1/x).(1/x).(1/x).(1/x).(1/x)=(1/x)\(^5\)