C.
\(T_{1_{ }_{ }}:T_{2_{ }}=\sqrt{\dfrac{m.k_2}{k_1.m}}=\sqrt{\dfrac{k_2}{k_1}}=\dfrac{1}{2}\)
\(\dfrac{k_2}{k_1}=\dfrac{1}{4}\)
\(\Rightarrow\left\{{}\begin{matrix}k_1=4k_2\\k_1+k_2=5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}k_2=1\\k_1=4\end{matrix}\right.\)
Câu 1:
T1 = 2
T2 = 2
=> T1 / T2 = Căn ( k2 / k1 ) = 1 / 2
=> k2 / k1 = 1 / 4
=> k1 = 4 k2
Ta có hệ:
=>
ta chọn câu C