\(\left|x+1\right|=2x-2\)
\(\Rightarrow\left[{}\begin{matrix}x+1=2x-2\\x+1=2-2x\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x+1-2x+2=0\\x+1-2+2x=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}-x+3=0\\3x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=\dfrac{1}{3}\end{matrix}\right.\)
Tổng 2 nghiệm = \(3+\dfrac{1}{3}=\dfrac{10}{3}\)