`(sqrt{4 + sqrt{7}} - sqrt{4 - sqrt{7}})^2`
`= 4 + sqrt{7} - 2 . sqrt{4 + sqrt{7}} . sqrt{4 - sqrt{7}} + 4 - sqrt{7}`
`= 8 - 2 . sqrt{(4 + sqrt{7}) .(4 - sqrt{7})}`
`= 8 - 2 . sqrt{16 - 7}`
`= 8 - 2 . sqrt{9}`
`= 8 - 2 . 3`
`= 8 - 6
`= 2`
Vậy ...
`(sqrt{4 + sqrt{7}} - sqrt{4 - sqrt{7}})^2`
`= 4 + sqrt{7} - 2 . sqrt{4 + sqrt{7}} . sqrt{4 - sqrt{7}} + 4 - sqrt{7}`
`= 8 - 2 . sqrt{(4 + sqrt{7}) .(4 - sqrt{7})}`
`= 8 - 2 . sqrt{16 - 7}`
`= 8 - 2 . sqrt{9}`
`= 8 - 2 . 3`
`= 8 - 6
`= 2`
Vậy ...
Tính \(T=\frac{4+\sqrt{7}}{2\sqrt{2}+\sqrt{4+\sqrt{7}}}+\frac{4-\sqrt{7}}{2\sqrt{2}-\sqrt{4-\sqrt{7}}}\)
Tính GTBT:
\(B=\frac{4+\sqrt{7}}{3\sqrt{2}+\sqrt{4+\sqrt{7}}}+\frac{4-\sqrt{7}}{3\sqrt{2}-\sqrt{4-\sqrt{7}}}\)
Tính:
\(\sqrt{4-\sqrt{7}}+\sqrt{4+\sqrt{7}}\)
tính
\(\sqrt{4-\sqrt{7}}-\sqrt{4+\sqrt{7}}-\sqrt{2}\)
giúp mình với
1) thực hiện phép tính
d)\(\dfrac{4}{\sqrt{7}-\sqrt{3}}+\dfrac{6}{3+\sqrt{3}}+\dfrac{\sqrt{7}-7}{\sqrt{7}-1}\)
e) \(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
giúp mk vs ạ mk cần gấp
B=\(\sqrt{4+\sqrt{7}}+\sqrt{4-\sqrt{7}}\)
tính dùm e nha
Tính
G.\(\sqrt{7-2\sqrt{6}}\)
H.\(\sqrt{13-4\sqrt{3}}\)
I. \(\sqrt{7-4\sqrt{3}}\)\(-2\)
J.\(\sqrt{15-6\sqrt{6}}\)+\(\sqrt{33-12\sqrt{6}}\)
Thực hiện phép tính ( rút gọn biểu thức )
a) \(\sqrt{2}\left(\sqrt{4+\sqrt{7}}+\sqrt{4-\sqrt{7}}\right)\)
b) \(\sqrt{2-\sqrt{3}}\) - \(\sqrt{2+\sqrt{3}}\)
tính
a, \(A=2\sqrt{12}-3\sqrt{48}+4\sqrt{75}\)
\(B=\sqrt{\frac{4-\sqrt{7}}{4+\sqrt{7}}}+\sqrt{\frac{4+\sqrt{7}}{4-\sqrt{7}}}\)
c, \(C=\frac{3-2\sqrt{3}}{\sqrt{3}}+\frac{6}{3+\sqrt{3}}\)
d,
Tính
a) \(\sqrt{7-4\sqrt{3}}-\sqrt{7+4\sqrt{3}}\)
b) \(\sqrt{4+\sqrt{7}} -\sqrt{4-\sqrt{7}}\)
c) \(\sqrt{4-\sqrt{10-2\sqrt{5}}}-\sqrt{4+\sqrt{10-2\sqrt{5}}}\)