\(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-4-3}{156}=-\dfrac{7}{156}\)
\(\dfrac{-52}{2028}+\dfrac{-39}{2028}=\dfrac{-7}{156}\)
\(=\dfrac{-4}{156}-\dfrac{3}{156}=\dfrac{-7}{156}\)
\(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-4-3}{156}=-\dfrac{7}{156}\)
\(\dfrac{-52}{2028}+\dfrac{-39}{2028}=\dfrac{-7}{156}\)
\(=\dfrac{-4}{156}-\dfrac{3}{156}=\dfrac{-7}{156}\)
Bài 1:So Sánh(nhanh nhất)
\(\dfrac{-13}{38}va\dfrac{29}{-88},\dfrac{-18}{31}va\dfrac{-1818}{3131}\)
Bài 2:Tính
a)\(\dfrac{-1}{39}+\dfrac{-1}{52}\)
b)\(\dfrac{-6}{9}+\dfrac{-12}{16}\)
Tìm x:
a) \(1\dfrac{3}{4}\) . x + \(1\dfrac{1}{2}\) = = \(\dfrac{-4}{5}\)
b) x ( \(\dfrac{1}{5}\) + \(\dfrac{1}{4}\) ) - ( \(\dfrac{1}{7}\) + \(\dfrac{1}{8}\) ) = 0
c) \(|\) x \(|\) = 3,5
d) \(|\) x \(|\) = -2,7
e) \(|\) 1 - x \(|\) + 0,73 = 3
f) 52 . 73 . 11x + 52 . 72 .11 = 0
g) (3 . 5 + 5 . 7)x + ( 3 . 5 + 5 . 7) + (3 . 5 + 5 . 7) = 0
h) 52 . 72 . 112x - 52 . 72 . 114 = 0
l) \(|\) x + \(\dfrac{3}{4}\) \(|\) - 5 = -2
6. Tính
\(A=\dfrac{4}{1.4}+\dfrac{4}{4.7}+\dfrac{4}{7.10}+...+\dfrac{4}{31.34}\)
\(B=1-5+5^2-5^3+5^4-...-5^{39}\)
\(39\dfrac{1}{3}:\dfrac{4}{5}-19\dfrac{1}{3}:\dfrac{4}{5}\)
a \(\dfrac{-4}{7}\) - \(\dfrac{5}{13}\) x \(\dfrac{-39}{25}\) + \(\dfrac{-1}{42}\) : \(\dfrac{-5}{6}\)
b \(\dfrac{2}{9}\) x [\(\dfrac{4}{45}\): ( \(\dfrac{1}{5}\) - \(\dfrac{2}{15}\)) + 1\(\dfrac{2}{3}\)] - \(\dfrac{-5}{27}\)
Tìm x,y:(áp dụng t/c của dãy tỉ số bằng nhau)
1/x:y=\(1\dfrac{2}{3}\)và x-y=60
2/\(\dfrac{x}{2}\)=\(\dfrac{y}{3}\)và \(x^2\)+\(y^2\)=52
\(\dfrac{2}{5}\)x = (\(\dfrac{1}{2}\))\(^3\) : \(\dfrac{1}{2}\)
:'>?
a, \(5^6\) : \(5^5\) + \(\left(\dfrac{4}{9}\right)^0\) b,\(\left(\dfrac{3}{7}\right)^{21}\) : \(\left(1-\dfrac{40}{49}\right)^3\) c, 3.\(\left(\dfrac{2}{3}\right)^3\) -\(\left(\dfrac{-52}{3}\right)^0\) +\(\dfrac{4}{9}\)
Mọi người giúp mình với
1 so sánh \(\dfrac{1}{2^{300}}\) và \(\dfrac{1}{300^{200}}\)
\(\dfrac{1}{5^{199}}\) và\(\dfrac{1}{3^{300}}\)
2 so sánh
5\(^{20}\)và 3\(^{34}\)
(-5)\(^{39}\)và -2\(^{91}\)