Question

Tính.

a, (x³-2x²-10x-7):(x²-7-3x)

b, (x³+4x²+8x+5):(x+1)

c, (x³-x²-13x-14):(x²-3x-7)

d, (x³+5x²+5x):(x+5)

Answer 1

a: \(=\dfrac{x^3-3x^2-7x+x^2-3x-7}{x^2-3x-7}=x+1\)

b:\(=\dfrac{x^3+x^2+3x^2+3x+5x+5}{x+1}=x^2+3x+5\)

c:\(=\dfrac{x^3-3x^2-7x+2x^2-6x-14}{x^2-3x-7}=x+2\)

d: \(=\dfrac{x^2\left(x+5\right)+5x+25-25}{x+5}=x^2+5-\dfrac{25}{x+5}\)