\(\dfrac{1}{3}+\dfrac{2}{9}\times\dfrac{3}{4}=\dfrac{1}{3}+\dfrac{1}{6}=\dfrac{6}{18}+\dfrac{3}{18}=\dfrac{9}{18}=\dfrac{1}{2}\)
\(\dfrac{1}{3}+\dfrac{2}{9}\times\dfrac{3}{4}=\dfrac{1}{3}+\dfrac{6}{36}=\dfrac{12}{36}+\dfrac{6}{36}=\dfrac{18}{36}=\dfrac{1}{2}\)
\(\dfrac{1}{3}+\dfrac{2}{9}x\dfrac{3}{4}=\dfrac{1}{3}+\dfrac{1}{6}=\dfrac{1}{2}\)