\(\dfrac{1}{10}+\dfrac{1}{2}:0,5-\dfrac{1}{4}:0,25+\dfrac{1}{8}:0,125\)
\(=\dfrac{1}{10}+\dfrac{1}{2}\times2-\dfrac{1}{4}\times4+\dfrac{1}{8}\times8\)
\(=\dfrac{1}{10}+1-1+1\)
\(=\dfrac{1}{10}+1=\dfrac{1}{10}+\dfrac{10}{10}=\dfrac{11}{10}\)
\(\dfrac{1}{10}+\dfrac{1}{2}\div0,5-\dfrac{1}{4}\div0,25+\dfrac{1}{8}\div0,125\)
= 0,1 + 0,5 x 2 - 0,25 x 4 + 0,125 x 8
= 0,1 + 1 - 1 + 1
= 1,1 - 1 +1
= 0,1 + 1
= 1,1
`#3107.101107`
\(\dfrac{1}{10}+\dfrac{1}{2}\cdot0,5-\dfrac{1}{4}\div0,25+\dfrac{1}{8}\div0,125\)
\(=\dfrac{1}{10}+\left(\dfrac{1}{2}\div0,5\right)-\left[\left(\dfrac{1}{2}\right)^2\div\left(0,5\right)^2\right]+\left(\dfrac{1}{2}\right)^3\div\left(0,5\right)^3\)
\(=\dfrac{1}{10}+\left(\dfrac{1}{2}\div0,5\right)-\left(\dfrac{1}{2}\div0,5\right)^2+\left(\dfrac{1}{2}\div0,5\right)^3\)
\(=\dfrac{1}{10}+1-1^2+1^3\)
\(=\dfrac{1}{10}+1\)
\(=\dfrac{11}{10}\)
\(\dfrac{1}{10}\) + \(\dfrac{1}{2}\) : 0,5 - \(\dfrac{1}{4}\) : 0,25 + \(\dfrac{1}{8}\) : 0,125
= 0,1 + \(\dfrac{1}{2}\)x 2 - \(\dfrac{1}{4}\) x 4 + \(\dfrac{1}{8}\) x 8
= 0,1 + 1 - 1 + 1
= (0,1 + 1) + (1 - 1)
= 1,1
