Lời giải:
$\frac{a}{b}=\frac{42}{66}=\frac{7}{11}$ rồi đó bạn, cần gì tìm $\frac{a}{b}$ nữa
Lời giải:
$\frac{a}{b}=\frac{42}{66}=\frac{7}{11}$ rồi đó bạn, cần gì tìm $\frac{a}{b}$ nữa
Tìm số tự nhiên a,b \(\dfrac{a}{b}=\dfrac{36}{45}\) biết BCNN \(\left(a,b\right)=300\)
Tìm \(\dfrac{\left(\left(4\right)^{-2}:\left(\dfrac{1}{3}\right)^2\right)\dfrac{^1}{2}}{\left(-\dfrac{1}{6}\right)^2}\)
A. 36 B.27 C. 48 D.- 36 E.-27
Bài 1: Rút gọn ( đưa vềphân sốtối giản, có mẫu dương)
a, \(\dfrac{36}{-42}\)
b,\(\dfrac{15.49}{-7.30}\)
c,\(\dfrac{\left(-7\right)^2.3^3}{3^2.\left(-7\right)^3}\)
Tìm x:
a) \(\dfrac{x}{4}=\dfrac{4}{x}\)
b) \(\dfrac{x+7}{15}=-\dfrac{24}{36}\)
c) \(\dfrac{x+1}{8}=\dfrac{2}{x+1}\)
d) \(\dfrac{2x-1}{\left(-3\right)^2}=\dfrac{\left(-3\right)^2}{2x-1}\)
\(a,\dfrac{-6}{11}:\left(\dfrac{3}{5}:\dfrac{4}{11}\right)\) b,\(\dfrac{7}{12}+\dfrac{5}{12}:6-\dfrac{11}{36}\)
\(c,\left(\dfrac{4}{5}+\dfrac{1}{2}\right):\left(\dfrac{3}{13}-\dfrac{8}{13}\right)\) \(d,\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}-1-\dfrac{7}{11}\right)\)
Giúp mik nha:>>
Tính hợp lý:
\(A=\dfrac{7}{12}+\dfrac{5}{12}:6-\dfrac{11}{36}\) \(B=\left(\dfrac{4}{5}+\dfrac{1}{2}\right):\left(\dfrac{3}{13}-\dfrac{8}{13}\right)\)
\(C=\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}+1-\dfrac{7}{11}\right)\)
tính
a)\(\dfrac{-10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
b)\(\dfrac{3}{14}:\dfrac{1}{28}-\dfrac{13}{21}:\dfrac{1}{28}+\dfrac{29}{42}:\dfrac{1}{28}-8\)
c)\(-1\dfrac{5}{7}.15+\dfrac{2}{7}\left(-15\right)+\left(-105\right).\left(\dfrac{2}{3}-\dfrac{4}{5}+\dfrac{1}{7}\right)\)
Tính hợp lý
\(A = \left(1-\dfrac{1}{25}\right)\left(1-\dfrac{1}{36}\right)\left(1-\dfrac{1}{49}\right)...\left(1-\dfrac{1}{10000}\right)\) B= \(\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{6}\right)\left(1-\dfrac{1}{10}\right)...\left(1-\dfrac{1}{50.101}\right)\)
Tìm x biết: a) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\) b) \(x-\dfrac{1}{8}=\dfrac{5}{8}\)
c) \(-\dfrac{1}{2}-\left(\dfrac{3}{2}+x\right)=-2\) d) \(x+\dfrac{1}{3}=\dfrac{-12}{5}.\dfrac{10}{6}\)