Question

tim x,y,z :

\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\) và x - 2y+3z= 14

Answer 1

chtt

Answer 2

HUHU!!! Làm gần xong rồi mãy bị lag

Answer 3

Ta có:

\(\frac{y-2}{3}=\frac{2.\left(y-2\right)}{2.3}=\frac{2y-4}{6}\)

\(\frac{z-3}{4}=\frac{3.\left(z-3\right)}{3.4}=\frac{3z-9}{12}\)

Theo t/c dãy tỉ số = nhau:

\(\frac{x-1}{2}=\frac{2y-4}{6}=\frac{3z-9}{12}=\frac{x-1-2y+4+3z-9}{2-6+12}=\frac{x-2y+3z-6}{8}=\frac{14-6}{8}=\frac{8}{8}=1\)

=> \(\frac{x-1}{2}=1\Rightarrow x-1=2\Rightarrow x=2+1=3\)

=> \(\frac{y-2}{3}=1\Rightarrow y-2=3\Rightarrow y=3+2=5\)

=> \(\frac{z-3}{4}=1\Rightarrow z-3=4\Rightarrow z=4+3=7\)

Vậy x=3; y=5; z=7.