Question

Tìm x

\(\sqrt{\left(x-3\right)^2}-7=0\)

Answer 1

\(\left[{}\begin{matrix}x-3-7=0\\x-3+7=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-4\end{matrix}\right.\)

Answer 2

\(\sqrt{\left(x-3\right)^2}-7=0\)

\(\Leftrightarrow\left|x-3\right|=7\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=7\\x-3=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=10\\x=-4\end{matrix}\right.\)

Answer 3

\(x-3-7=0\)

\(x-10=0\)

\(x=10\)

Vậy \(x=10\)