\(2^{x+2}-2^{x+1}=32\)
\(\Rightarrow2^x\times2^2-2^x\times2=32\)
\(\Rightarrow2^x\times\left(2^2-2\right)=32\)
\(\Rightarrow2^x\times2=32\)
\(\Rightarrow2^x=32:2\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
Vậy x = 4
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\(2^{x+2}-2^{x+1}=32.\)
\(\Leftrightarrow2^x.2^2-2^x.2=32\)
\(\Leftrightarrow2^x.\left(2^2-2\right)=32\)
\(\Leftrightarrow2^x.2=32\)
\(\Leftrightarrow2^x=16\)
\(\Leftrightarrow2^x=2^4\)
\(\Leftrightarrow x=4\)