Question

Tìm x

\(\left(x^2-4\right)\sqrt{x}=0\)

Answer 1

ĐKXĐ: x>=0

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=0\\x^2-4=0\end{matrix}\right.\Leftrightarrow x\in\left\{0;2\right\}\)

Answer 2

Tham khảo

Answer 3

ĐKXĐ : \(x\ge0\) 

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x}=0\\x^2-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(tm\right)\\x^2=4\Rightarrow\left[{}\begin{matrix}x=2\left(tm\right)\\x=-2\end{matrix}\right.\end{matrix}\right.\)

vậy ........