Question

tìm x:
\(\left(x-2\right)^2-\left(x-3\right)\left(x+3\right)=6\)

Answer 1

\((x-2)^2-(x-3)(x+3)=6\\\Rightarrow x^2-2\cdot x\cdot2+2^2-(x^2-3^2)=6\\\Rightarrow x^2-4x+4-(x^2-9)=6\\\Rightarrow x^2-4x+4-x^2+9=6\\\Rightarrow -4x+13=6\\\Rightarrow-4x=6-13\\\Rightarrow-4x=-7\\\Rightarrow x=\dfrac{7}{4}\)