Question

Tìm \(x\):

\(c.\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)        \(g.x-[\dfrac{17}{12}-\left(\dfrac{-3}{7}+\dfrac{5}{3}\right)]=\dfrac{-1}{3}\)

Answer 1

c: =>x+2/5=11/12-2/3=11/12-8/12=3/12=1/4

=>x=1/4-2/5=0,25-0,4=-0,15

g: =>x=-1/3+17/12-(-3/7+5/3)

=>x=17/12-4/12+3/7-5/3

=>x=13/12-20/12+3/7=-7/12+3/7=-13/84

Answer 2

`c) 11/12-(2/5+x)=2/3`

`⇒2/5+x=11/12-2/3`

`⇒2/5+x=11/12-8/12`

`⇒x=1/4-2/5`

`⇒x=5/20-8/20`

`⇒x= -3/20`

`g) x - [ 17/12 - (-3/7 + 5/3)] = -1/3`

`=> x - [ 17/12 - ( - 9/21 + 35/21 )] = -1/3`

`=> x - [ 17/12 - (-26/21)] = -1/3`

`=> x - [ 17/12 - 26/21 ] = -1/3`

`=> x - 15/84 = -1/3`

`=> x = -1/3 + 15/84`

`=> x = -28/84 + 15/84`

`=> x = -13/84`