Ta có: \(2x+\dfrac{1}{4}=-1\)
\(\Leftrightarrow2x=-\dfrac{5}{4}\)
hay \(x=-\dfrac{5}{8}\)
Vậy: \(x=-\dfrac{5}{8}\)
\(\dfrac{2x+1}{4}=-1\)
\(\Leftrightarrow2x+1=-4\)
\(\Leftrightarrow2x=-4-1=-5\)
\(\Leftrightarrow x=-\dfrac{5}{2}\)
2x=-1-1/4
2x=-5/4
x=-5/8
Chúc em học tốt^^