Question

tìm x

b ,3 (x-2) + 2( 3x - 5) = 10

c, 2x - (3x+1) = 5x-2

d, 3x + 2 = (-5) + 6 

Answer 1

\(b,3\left(x-2\right)+2\left(3x-5\right)=10\\ \Leftrightarrow3x-6+6x-10=10\\ \Leftrightarrow3x+6x=10+10+6\\ \Leftrightarrow9x=26\\ \Leftrightarrow x=\dfrac{26}{9}\\ c,2x-\left(3x+1\right)=5x-2\\ \Leftrightarrow2x-3x-1=5x-2\\ \Leftrightarrow2x-3x-5x=-2+1\\ \Leftrightarrow-6x=-1\\ \Leftrightarrow x=\dfrac{1}{6}\\ d,3x+2=-5+6 \\ \Leftrightarrow3x=-5+6-2\\ \Leftrightarrow3x=-2\\ \Leftrightarrow x=-\dfrac{1}{3}\)

Answer 2

a: =>3x-6+6x-10=10

=>9x=26

=>x=26/9

Answer 3

b: =>5x-2=2x-3x-1

=>5x-2=-x-1

=>6x=1

=>x=1/6

d: =>3x+2=1

=>3x=-1

=>x=-1/3

Answer 4

b,3(x−2)+2(3x−5)=10

⇔3x−6+6x−10=10

⇔3x+6x=10+10+6⇔9x=26

⇔x=26/9

c,2x−(3x+1)=5x−2

⇔2x−3x−1=5x−2⇔2x−3x−5x=−2+1

⇔−6x=−1

⇔x=1/6

d,3x+2=−5+6

⇔3x=−5+6−2

⇔3x=−2

⇔x=−1/3