a) \(\left(x-1\right)^3=27\)
\(\left(x-1\right)^3=3^3\)
\(x-1=3\)
\(x=3+1\)
\(x=4\)
Vậy \(x=4\)
b) \(\left(x+2\right)^2=16\)
\(\left(x+2\right)^2=4^2\)
\(x+2=4\)
\(x=4-2\)
\(x=2\)
Vậy \(x=2\)
b)!x+2!=4
\(\orbr{\begin{cases}x+2=-4\\x+2=4\end{cases}}\Rightarrow\orbr{\begin{cases}x=-6\\x=2\end{cases}}\)