Question

tìm x:

(2x-5)^2-(3+2x)^2=0

Answer 1

Đề thiếu rồi bạn

Answer 2

\(\left(2x-5-3-2x\right)\left(2x-5+3+2x\right)=-8\left(4x-2\right)\)

Answer 3

\(\left(2x-5\right)^2-\left(3+2x\right)^2=0\)

\(\Rightarrow\left(2x-5-3-2x\right)\left(2x-5+3+2x\right)=0\)

\(\Rightarrow-16\left(2x-1\right)=0\)

\(\Rightarrow x=\dfrac{1}{2}\)

Answer 4

\(\left(2x-5\right)^2-\left(2x+3\right)^2=0\)

\(\Leftrightarrow2x-5+2x+3=0\)

\(\Leftrightarrow4x=2\)

hay \(x=\dfrac{1}{2}\)