`12 xx x - 1 = 0`
`12 xx x = 1`
`=> x = 1/12`
12xX-1=0
-> 12xX=1
-->X=\(\dfrac{1}{12}\)
12 x X = 0 + 1
12 x X = 1
x = 1 : 12
x = 1/12
12 x X - 1 = 0
12 x X = 0 + 1
12 x X = 1
X = 1 : 12
X = 1/12
vậy x = 1/12
12 x X = 0 + 1
12 x X = 1
x = 1 : 12
x = \(\dfrac{1}{12}\)