\(\dfrac{x}{2}=\dfrac{x+2}{3}\)
\(x.3=\left(x+2\right).2\)
\(x.3=2x+2.2\)
\(x.3=2x+4\)
\(3x-2x=4\)
\(x\left(3-2\right)=4\)
\(x1=4\)
\(x=4:1\)
\(x=4\)
Vậy \(x=4\)
\(\dfrac{x}{2}=\dfrac{x+2}{3}\)
=>3x=2(x+2)
=>3x=2x+4
=>x=4
` x/2 = (x+2)/3 `
` 3x = 2.(x+2)`
` 3x = 2x + 4`
` x = 4`
`x/2 + (x+2)/3`
` 3x = 2.(x+2)`
` 3x = 2x + 4`
` x = 4`
Vậy `x=4`