\((x-5)(x+5)-(x+3)^2=(x+1)^2-(x+4)(x-4)\\\Leftrightarrow x^2-25-(x^2+6x+9)=x^2+2x+1-(x^2-16)\\\Leftrightarrow x^2-25-x^2-6x-9=x^2+2x+1-x^2+16\\\Leftrightarrow -6x-34=2x+17\\\Leftrightarrow -6x-2x=17+34\\\Leftrightarrow -8x=51\\\Leftrightarrow x=\dfrac{-51}{8}\\\text{#}Toru\)