Question

Tìm x

Answer 1

Ta có 60^o+90^o+70^o+x=360^o

\(\Rightarrow\)H₁=360-60-90-70=140^o

Mà H₁ kề bù với x \(\Rightarrow\)x=40^o

Answer 2

xét tứ giác FGHE có: \(\widehat{F}\)+\(\widehat{G}\)+\(\widehat{E}\)+\(\widehat{EHG}\)= 360'

⇒\(\widehat{EHG}\)= 360'-\(\widehat{F}\)-\(\widehat{G}\)-\(\widehat{E}\)=360'-90'-70'-60'=140'

Ta lại có: \(\widehat{EHG}\)+x=180'( 2 góc kề bù)

⇒x=180'-\(\widehat{EHG}\)=180'-140'=40'

Vậy x=40'