a, 36 chia hết cho x+1
=> x + 1 E Ư(36) = {1;2;3;4;6;9;12;18;36}
=> x = {0;1;2;3;5;8;11;17;35}
b,25 chia hết cho 2x+1 tương tự
a) 36 chia hết cho x + 1 \(\Rightarrow x+1\inƯ\left(36\right)=\left\{1;2;3;4;6;9;12;18;36\right\}\)
\(\Rightarrow x\in\left\{0;1;2;3;5;8;11;17;35\right\}\)
a) 25 chia hết cho 2x + 1 \(\Rightarrow2x+1\inƯ\left(25\right)=\left\{1;5;25\right\}\)
\(\Rightarrow2x\in\left\{0;4;24\right\}\)\(\Rightarrow x\in\left\{0;2;12\right\}\)
vi 36 chia het cho x+1 suy ra( x+1) thuoc U(36)
u(36)= { 1, 2,3,4,6,9,12,18,36 }
Suy ra x+1thuoc{1,2,3,4,6,9,12,18,36} Suy ra x thuoc {0,1,2,3,5,8,11,17,35}
Vay x thuoc {0,1,2,3,5,8,11,17,35}