\(\dfrac{-3}{x+1}=\dfrac{4}{2-2x}\)
\(\Rightarrow\left(-3\right).\left(2-2x\right)=4.\left(x+1\right)\)
\(\Rightarrow-6+6x=4x+4\)
\(\Rightarrow6x-4x=4+6\)
\(\Rightarrow2x=10\)
\(\Rightarrow x=10:2\)
\(\Rightarrow x=5\)
=>-3(2-2x)=4(x+1)
=>4x+4=6x-6
=>2x=-10
=>x=-5
`#lv`
`3/(x+1)=4/(2-2x)`
`=>-3.(2-2x)=4.(x+1)`
`=>-6+6x=4x+4`
`=>6x-4x=4+6`
`=>2x=10`
`=>x=5`
Vậy `x=5`