ĐKXĐ: \(\left\{{}\begin{matrix}x>=0\\x\ne9\end{matrix}\right.\)
\(\dfrac{1}{\sqrt{x}-3}>=-\dfrac{1}{3}\)
=>\(\dfrac{1}{\sqrt{x}-3}+\dfrac{1}{3}>=0\)
=>\(\dfrac{3+\sqrt{x}-3}{3\left(\sqrt{x}-3\right)}>=0\)
=>\(\dfrac{\sqrt{x}}{3\left(\sqrt{x}-3\right)}>=0\)
=>\(\sqrt{x}-3>0\)
=>\(\sqrt{x}>3\)
=>x>9