Question

tìm x, biết:

x² +10x+25=0

Answer 1

`x^2 +10x+25=0`

`=>x^2 + 2.x.5+5^2 =0`

`=>(x+5)^2 =0`

`=>x+5=0`

`=>x=-5`

Answer 2

\(x^2+10x+25=0\)

\(\left(x^2+2.x.5+5^2\right)=0\)

\(\left(x+5\right)^2=0\)

\(\Rightarrow x+5=0\)

     \(x\)        \(=0-5=-5\)

Answer 3

x 2 + 10 x + 25 = 0 ⇒ x 2 + 2 . x .5 + 5 2 = 0 ⇒ ( x + 5 ) 2 = 0 ⇒ x + 5 = 0 ⇒ x = − 5

Answer 4

` x^2+10x+25=0 `

` => (x+5)^2=0 `

` => x+5=0 `

` => x=-5`

Vậy `x=5`