\(\Rightarrow4x^2-12x+9-x^2+9=3x^2+5x-2-15x\\ \Rightarrow-2x=-20\Rightarrow x=10\)
\(\Leftrightarrow4x^2-12x+9-x^2+9=3x^2+5x-2-15x\)
\(\Leftrightarrow-2x=-20\Leftrightarrow x=10\)
Ta có: \(\left(2x-3\right)^2-\left(x-3\right)\left(x+3\right)=\left(3x-1\right)\left(x+2\right)-15x\)
\(\Leftrightarrow4x^2-12x+9-x^2+9=3x^2+6x-x-2-15x\)
\(\Leftrightarrow-12x+18=-10x-2\)
\(\Leftrightarrow x=10\)