Question

tìm x biết 

3x^2-x=0

2x(x-5)-x(3+2x)=26

Answer 1

3x^2-x = 0

x(3x-1) = 0

TH1: x = 0

TH2: 3x-1 = 0

x= 1/3

Answer 2

b) Ta có: 2x(x – 5) – x(3 + 2x) = 26

      ⇔ 2 – 10x – 3x – 2 =26

      ⇔ - 13x = 26

  

      ⇔ x = - 2

Answer 3

2x (x-5) - x(3+2x) = 26

2x^2 - 10x - 3x - 2x^2 = 26

-13x = 26

x = -2