Question

tìm x : a)3^x+2+3^x+1-3^x=33

Answer 1

\(3^{x+2}+3^{x+1}-3^x=33\)

=>\(3^x\cdot9+3^x\cdot3-3^x=33\)

=>\(3^x\cdot11=33\)

=>\(3^x=3\)

=>x=1

Answer 2

\(3^{x+2}+3^{x+1}-3^x=33\\ 3^x.3^2+3^x.3-3^x=33\\ 3^x.\left(9+3-1\right)=33\\ 3^x.11=33\\ 3^x=33:11\\ 3^x=3\\ \Rightarrow x=1\)

Answer 3

\(a,3^{x+2}+3^{x+1}-3^x=33\)

\(3^x.9+3^x.3-3^x.1=33\)

\(3^x.\left(9+3-1\right)=33\)

\(3^x.11=33\)

\(3^x=33:11\)

\(3^x=3\)

\(=>x=1\)

Vậy `x = 1`