a)\(\dfrac{x}{4}=\dfrac{16}{128}\)
\(\Leftrightarrow\dfrac{x}{4}=\dfrac{1}{8}\)
\(\Rightarrow x=\dfrac{1.4}{8}=\dfrac{1}{2}\)
b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\)
\(\Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\)
\(\Rightarrow-x=\dfrac{11.5}{6}=\dfrac{-55}{6}\)
c)\(4,25:8=-3,5:x\)
\(\Leftrightarrow\dfrac{17}{32}=\dfrac{-3,5}{x}\)
\(\Rightarrow x=\dfrac{\left(-3,5\right).32}{17}=-\dfrac{112}{17}\)
Tìm x
a)\(\dfrac{x}{4}\)=\(\dfrac{16}{128}\)
\(\Rightarrow\)x.128=16.4
x.128=64
x=64:128
x=\(\dfrac{1}{2}\)
Vậy x=\(\dfrac{1}{2}\)
b)\(1\dfrac{5}{6}\)=\(\dfrac{-x}{5}\)
\(\dfrac{11}{6}\)=\(\dfrac{-x}{5}\)
-x:5=\(\dfrac{11}{6}\)
-x=\(\dfrac{11}{6}\).5
-x=\(\dfrac{55}{6}\)
\(\Rightarrow\)x=\(\dfrac{-55}{6}\)
Vậy x=\(\dfrac{-55}{6}\)
c)4,25:8 = -3,5:x
-3,5:x=\(\dfrac{17}{4}\)
x=-3,5:\(\dfrac{17}{4}\)
x=\(\dfrac{14}{17}\)
Vậy x=\(\dfrac{14}{17}\)
a, Ta có : \(\dfrac{x}{4}\)= \(\dfrac{16}{128}\)
\(\Rightarrow\)4 . 16 = x . 128
\(\Rightarrow\) x = (4 . 16 ) : 128
\(\Rightarrow\) x = \(\dfrac{1}{2}\)
b, Ta có : 1\(\dfrac{5}{6}\) = \(\dfrac{-x}{5}\)
\(\Leftrightarrow\dfrac{11}{6}\) = \(\dfrac{-x}{5}\)
\(\Rightarrow\)11 . 5 = 6 . ( \(-x\) )
\(\Rightarrow\)\(-x\) = (11. 5) : 6
\(\Rightarrow\) \(-x\) = \(\dfrac{-55}{6}\)
\(\Rightarrow\) \(x\) = \(\dfrac{55}{6}\)
c,Ta có : 4 , 25 : 8 = \(-3,5\) : x
\(\Rightarrow\) \(\dfrac{17}{32}\) = \(\dfrac{-3,5}{x}\)
\(\Rightarrow\) 17 . x = \(-3,5\) . 32
\(\Rightarrow\) x = ( \(-3,5\) . 32 ): 17
\(\Rightarrow\) x = \(\dfrac{-112}{17}\)
