Question

Tìm X: (1/4 x X -1/8) x 3/4 = 1/4
Các bạn giúp mình nha mình cần gấp :)

Answer 1

Đề hơi khó hiểu bn nhé

Answer 2

\(\left(\dfrac{1}{4}x-\dfrac{1}{8}\right).\dfrac{3}{4}=\dfrac{1}{4}\)

\(\dfrac{1}{4}x-\dfrac{1}{8}=\dfrac{1}{4}:\dfrac{3}{4}=\dfrac{1}{3}\)

\(\dfrac{1}{4}x=\dfrac{1}{3}+\dfrac{1}{8}=\dfrac{11}{24}\)

\(x=\dfrac{11}{24}:\dfrac{1}{4}=\dfrac{11}{6}\)

Answer 3

\(\left(\dfrac{1}{4}x\times\dfrac{-1}{8}\right)\times\dfrac{3}{4}=\dfrac{1}{4}< =>\dfrac{-x}{32}\times\dfrac{3}{4}=\dfrac{1}{4}< =>\dfrac{-x}{32}=\dfrac{1}{4}:\dfrac{3}{4}< =>\dfrac{-x}{32}=\dfrac{1}{3}< =>x=\dfrac{1}{3}\times\left(-32\right)< =>x=\dfrac{-32}{3}\)

Answer 4

\(\left(\dfrac{1}{4}x-\dfrac{1}{8}\right)\cdot\dfrac{3}{4}=\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{1}{4}x-\dfrac{1}{8}=\dfrac{1}{4}:\dfrac{3}{4}=\dfrac{1}{3}\)

\(\Leftrightarrow x\cdot\dfrac{1}{4}=\dfrac{1}{3}+\dfrac{1}{8}=\dfrac{11}{24}\)

\(\Leftrightarrow x=\dfrac{11}{6}\)