a) \(\left(4x-1\right)^2=9\)
\(\left(4x-1\right)^2=3^2\)
\(\Rightarrow4x-1=3\)
\(\Rightarrow4x=4\)
\(\Rightarrow x=1\)
vay \(x=1\)
b) \(3^{2x-3}=9\)
\(3^{2x-3}=3^2\)
\(\Rightarrow2x-3=2\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\frac{5}{2}\)
vay \(x=\frac{5}{2}\)
a. (4xX-1)^2 = 9
(4xX-1)^2 = 3^2
4xX-1 = 3
4xX =3+1
4xX = 4
X =4:4
X = 1
a)(4.x-1)^2=9 b)3^2.x-3=9
(4.x-1)^2=3^2 3^2.x=9+3
4.x-1=3 3^2.x=12
4.x=3+1 9.x=12
4.x=4 x=12:9
4/4=x x=4/3
x=1 vậy x=4/3
vậy x=1
nhớ tk nhe mn
