\(\left(3x-2^4\right)7^3=2\cdot7^4\)
\(3x-2^4=2\cdot7^4:7^3\)
\(3x-16=14\)
\(3x=30\)
\(x=10\)
ta co: (3×x-2^4)×7^3=2*7^4
3*x-16=2*7^4÷7^3
3*x-16=14
3*x=14+16
3*x=30
x=10
(3.x-24).73=4802
3.x-24 =4802:73=14
3.x =14+24=30
x =30:3=10
Vậy x=10
(3*x-16)*343=4082
(3*x-16)=4082/343
3*x-16=4082/343
x=9 dư
(3*x-16)=2.7^4/7^3
(3.x-16)=2.7
3.x=16+14
3.x=30
x=30/3
x=10
vậy x=10