Question

tìm số tự nhiên n biết:
c:(6^n -88):2^5=2^2
d) 512 : 2^n= 2^3

Answer 1

\(c,\left(6^n-88\right):32=4\\ 6^n-88=128\\ 6^n=216\\ 6^n=6^3\\ n=3\\ d,512:2^n=8\\ 2^n=512:8\\ 2^n=64\\ 2^n=2^6\\ n=6\)

Answer 2

c,(6ⁿ-88):2⁵=2²

<=> 6ⁿ-88=2².2⁵

<=>6ⁿ - 88 = 128

<=> 6ⁿ =128+88

<=>6ⁿ=216

<=>6ⁿ=6³

Vậy n = 3

d,512:2ⁿ = 2³

<=> 2ⁿ  = 512 : 2³

<=> 2ⁿ = 64

<=>2ⁿ = 2⁶

Vậy n=6