y) \(\dfrac{x+2}{4}=\dfrac{3}{6}\)
\(\Leftrightarrow6.\left(x+2\right)=4.3\\ \Leftrightarrow6x+12=12\\ \Leftrightarrow6x=0\\ \Leftrightarrow x=0\)
Vậy x = 0
z) \(\dfrac{2x}{49}=\dfrac{-2}{7}\)
\(\Leftrightarrow2x.7=\left(-2\right).49\\ \Leftrightarrow14x=-98\\ \Leftrightarrow x=-7\)
Vậy x = -7
y) (x + 2)/4 = 3/6
x + 2 = 1/2 . 4
x + 2 = 2
x = 2 - 2
x = 0
z) 2x/49 = -2/7
2x = -2/7 . 49
2x = -14
x = -14 : 2
x = -7
y) \(\dfrac{x+2}{4}=\dfrac{3}{6}\)
\(\Rightarrow6\cdot\left(x+2\right)=3\cdot4\)
\(\Rightarrow6\cdot\left(x+2\right)=12\)
\(\Rightarrow x+2=12:6\)
\(\Rightarrow x+2=2\)
\(\Rightarrow x=2-2=0\left(tm\right)\)
Vậy: \(x=0\)
z) \(\dfrac{2x}{49}=\dfrac{-2}{7}\)
\(\Rightarrow7\cdot2x=-2\cdot49\)
\(\Rightarrow14x=-98\)
\(\Rightarrow x=-98:14=-7\left(tm\right)\)
Vậy: \(x=-7\).
