a) \(\left|2x+1\right|-19=-7\)
\(\Rightarrow\left|2x+1\right|=12\)
\(\Rightarrow\orbr{\begin{cases}2x+1=12\\2x+1=-12\end{cases}\Rightarrow}\orbr{\begin{cases}2x=11\\2x=-13\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=\frac{13}{2}\end{cases}}}\)
Vậy \(x\in\left\{\frac{11}{2};\frac{13}{2}\right\}\)
a,\(/2x+1/-19=-7\)
\(=>/2x+1/=-7+19=12\)
\(=>\orbr{\begin{cases}2x+1=12\\2x+1=-12\end{cases}}\)
\(=>\orbr{\begin{cases}x=\frac{12-1}{2}=\frac{11}{2}\\x=\frac{-12-1}{2}=-\frac{13}{2}\end{cases}}\)
b,\(12-2\left(-x+3\right)^2=-38\)
\(=>2\left(-x+3\right)^2=12+38=50\)
\(=>\left(-x+3\right)^2=\frac{50}{2}=25=\pm5^2\)
\(=>\orbr{\begin{cases}-x+3=5\\-x+3=-5\end{cases}}=>\orbr{\begin{cases}-x=2\\-x=-8\end{cases}=>\orbr{\begin{cases}x=-2\\x=8\end{cases}}}\)
b) \(12-2\left(-x+3\right)^2=-38\)
\(\Rightarrow2\left(-x+3\right)^2=50\)
\(\Rightarrow\left(-x+3\right)^2=25\)
\(\Rightarrow\orbr{\begin{cases}\left(-x+3\right)^2=5^2\\\left(-x+3\right)^2=\left(-5\right)^2\end{cases}\Rightarrow\orbr{\begin{cases}-x+3=5\\-x+3=-5\end{cases}}}\)
\(\Rightarrow\orbr{\begin{cases}-x=2\\-x=-8\end{cases}}\Rightarrow\orbr{\begin{cases}x=-2\\x=8\end{cases}}\)
Vậy \(x\in\left\{-2;8\right\}\)
Số nguyên tố nha các bạn
\(a.|2x+1|-19=-7\)
\(\Rightarrow|2x+1|=12\)
\(\Rightarrow \orbr{\begin{cases}2x+1=12\\2x+1=-12\end{cases}} \Rightarrow\orbr{\begin{cases}2x=11\\2x=-13\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{11}{2}\\x=\frac{13}{2}\end{cases}}\)
\(x\in\left\{\frac{11}{2};\frac{13}{2}\right\}\)
