\(\left(x-2\right)^2=4\)
\(\Rightarrow\left(x-2\right)^2=\left(\pm2\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x-2=2\\x-2=-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\left(tm\right)\\x=0\left(tm\right)\end{matrix}\right.\)
Vậy \(x\in\left\{0;4\right\}\).
Bạn chỉnh lại môn học của câu hỏi này nhé.
\(\left(x-2\right)^2=4\)
\(\left(x-2\right)^2=2^2\)
\(\Rightarrow x-2=2\left(hay\right)x-2=-2\)
\(x=2+2\) \(x=-2+2\)
\(x=4\) \(x=0\)
Vậy \(x\in\left\{4;0\right\}\)
\(\left(x-2\right)^2=4\)
\(\Rightarrow x-2=\pm4\)
\(TH1:x-2=2\Rightarrow x=4\left(tm\right)\)
\(TH2:x-2=-2\Rightarrow x=0\left(ktm\right)\)
Vậy...
