Từ \(xy=\frac{x}{y}\Rightarrow xy^2=x\)
\(\Rightarrow y^2=1\Rightarrow y=\pm1\)
Nếu y=1 \(\Rightarrow x+y=x\Rightarrow x+1=x\)\(\Rightarrow1=0\left(loai\right)\)
Nếu y=-1 \(\Rightarrow x+\left(-1\right)=-x\Rightarrow x=\frac{1}{2}\)Vậy \(y=-1;x=\frac{1}{2}\)